Integrand size = 11, antiderivative size = 17 \[ \int \frac {(a+b x)^7}{x^9} \, dx=-\frac {(a+b x)^8}{8 a x^8} \]
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Time = 0.00 (sec) , antiderivative size = 17, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {37} \[ \int \frac {(a+b x)^7}{x^9} \, dx=-\frac {(a+b x)^8}{8 a x^8} \]
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Rule 37
Rubi steps \begin{align*} \text {integral}& = -\frac {(a+b x)^8}{8 a x^8} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(87\) vs. \(2(17)=34\).
Time = 0.00 (sec) , antiderivative size = 87, normalized size of antiderivative = 5.12 \[ \int \frac {(a+b x)^7}{x^9} \, dx=-\frac {a^7}{8 x^8}-\frac {a^6 b}{x^7}-\frac {7 a^5 b^2}{2 x^6}-\frac {7 a^4 b^3}{x^5}-\frac {35 a^3 b^4}{4 x^4}-\frac {7 a^2 b^5}{x^3}-\frac {7 a b^6}{2 x^2}-\frac {b^7}{x} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(77\) vs. \(2(15)=30\).
Time = 0.17 (sec) , antiderivative size = 78, normalized size of antiderivative = 4.59
method | result | size |
gosper | \(-\frac {8 b^{7} x^{7}+28 a \,b^{6} x^{6}+56 a^{2} b^{5} x^{5}+70 a^{3} b^{4} x^{4}+56 a^{4} b^{3} x^{3}+28 a^{5} b^{2} x^{2}+8 a^{6} b x +a^{7}}{8 x^{8}}\) | \(78\) |
norman | \(\frac {-b^{7} x^{7}-\frac {7}{2} a \,b^{6} x^{6}-7 a^{2} b^{5} x^{5}-\frac {35}{4} a^{3} b^{4} x^{4}-7 a^{4} b^{3} x^{3}-\frac {7}{2} a^{5} b^{2} x^{2}-a^{6} b x -\frac {1}{8} a^{7}}{x^{8}}\) | \(79\) |
risch | \(\frac {-b^{7} x^{7}-\frac {7}{2} a \,b^{6} x^{6}-7 a^{2} b^{5} x^{5}-\frac {35}{4} a^{3} b^{4} x^{4}-7 a^{4} b^{3} x^{3}-\frac {7}{2} a^{5} b^{2} x^{2}-a^{6} b x -\frac {1}{8} a^{7}}{x^{8}}\) | \(79\) |
default | \(-\frac {7 a^{5} b^{2}}{2 x^{6}}-\frac {a^{6} b}{x^{7}}-\frac {7 a^{2} b^{5}}{x^{3}}-\frac {b^{7}}{x}-\frac {7 a \,b^{6}}{2 x^{2}}-\frac {35 a^{3} b^{4}}{4 x^{4}}-\frac {7 a^{4} b^{3}}{x^{5}}-\frac {a^{7}}{8 x^{8}}\) | \(80\) |
parallelrisch | \(\frac {-8 b^{7} x^{7}-28 a \,b^{6} x^{6}-56 a^{2} b^{5} x^{5}-70 a^{3} b^{4} x^{4}-56 a^{4} b^{3} x^{3}-28 a^{5} b^{2} x^{2}-8 a^{6} b x -a^{7}}{8 x^{8}}\) | \(80\) |
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Leaf count of result is larger than twice the leaf count of optimal. 77 vs. \(2 (15) = 30\).
Time = 0.22 (sec) , antiderivative size = 77, normalized size of antiderivative = 4.53 \[ \int \frac {(a+b x)^7}{x^9} \, dx=-\frac {8 \, b^{7} x^{7} + 28 \, a b^{6} x^{6} + 56 \, a^{2} b^{5} x^{5} + 70 \, a^{3} b^{4} x^{4} + 56 \, a^{4} b^{3} x^{3} + 28 \, a^{5} b^{2} x^{2} + 8 \, a^{6} b x + a^{7}}{8 \, x^{8}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 83 vs. \(2 (14) = 28\).
Time = 0.27 (sec) , antiderivative size = 83, normalized size of antiderivative = 4.88 \[ \int \frac {(a+b x)^7}{x^9} \, dx=\frac {- a^{7} - 8 a^{6} b x - 28 a^{5} b^{2} x^{2} - 56 a^{4} b^{3} x^{3} - 70 a^{3} b^{4} x^{4} - 56 a^{2} b^{5} x^{5} - 28 a b^{6} x^{6} - 8 b^{7} x^{7}}{8 x^{8}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 77 vs. \(2 (15) = 30\).
Time = 0.19 (sec) , antiderivative size = 77, normalized size of antiderivative = 4.53 \[ \int \frac {(a+b x)^7}{x^9} \, dx=-\frac {8 \, b^{7} x^{7} + 28 \, a b^{6} x^{6} + 56 \, a^{2} b^{5} x^{5} + 70 \, a^{3} b^{4} x^{4} + 56 \, a^{4} b^{3} x^{3} + 28 \, a^{5} b^{2} x^{2} + 8 \, a^{6} b x + a^{7}}{8 \, x^{8}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 77 vs. \(2 (15) = 30\).
Time = 0.29 (sec) , antiderivative size = 77, normalized size of antiderivative = 4.53 \[ \int \frac {(a+b x)^7}{x^9} \, dx=-\frac {8 \, b^{7} x^{7} + 28 \, a b^{6} x^{6} + 56 \, a^{2} b^{5} x^{5} + 70 \, a^{3} b^{4} x^{4} + 56 \, a^{4} b^{3} x^{3} + 28 \, a^{5} b^{2} x^{2} + 8 \, a^{6} b x + a^{7}}{8 \, x^{8}} \]
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Time = 0.04 (sec) , antiderivative size = 77, normalized size of antiderivative = 4.53 \[ \int \frac {(a+b x)^7}{x^9} \, dx=-\frac {\frac {a^7}{8}+a^6\,b\,x+\frac {7\,a^5\,b^2\,x^2}{2}+7\,a^4\,b^3\,x^3+\frac {35\,a^3\,b^4\,x^4}{4}+7\,a^2\,b^5\,x^5+\frac {7\,a\,b^6\,x^6}{2}+b^7\,x^7}{x^8} \]
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